MathDB

2019 AMC 12/AHSME

Part of AMC 12/AHSME

Subcontests

(20)

Right triangles (2019 AMC 12B #12)

Right triangle ACDACD with right angle at CC is constructed outwards on the hypotenuse AC\overline{AC} of isosceles right triangle ABCABC with leg length 11, as shown, so that the two triangles have equal perimeters. What is sin(2BAD)\sin(2\angle BAD)? [asy] /* Geogebra to Asymptote conversion, documentation at artofproblemsolving.com/Wiki go to User:Azjps/geogebra */ import graph; size(8.016233639805293cm); real labelscalefactor = 0.5; /* changes label-to-point distance */ pen dps = linewidth(0.7) + fontsize(10); defaultpen(dps); /* default pen style */ pen dotstyle = black; /* point style */ real xmin = -4.001920114613276, xmax = 4.014313525192017, ymin = -2.552570341575814, ymax = 5.6249093771911145; /* image dimensions */
draw((-1.6742337260757447,-1.)--(-1.6742337260757445,-0.6742337260757447)--(-2.,-0.6742337260757447)--(-2.,-1.)--cycle, linewidth(2.)); draw((-1.7696484586262846,2.7696484586262846)--(-1.5392969172525692,3.)--(-1.7696484586262846,3.2303515413737154)--(-2.,3.)--cycle, linewidth(2.)); /* draw figures */ draw((-2.,3.)--(-2.,-1.), linewidth(2.)); draw((-2.,-1.)--(2.,-1.), linewidth(2.)); draw((2.,-1.)--(-2.,3.), linewidth(2.)); draw((-0.6404058554606791,4.3595941445393205)--(-2.,3.), linewidth(2.)); draw((-0.6404058554606791,4.3595941445393205)--(2.,-1.), linewidth(2.)); label("DD",(-0.9382446143428628,4.887784444795223),SE*labelscalefactor,fontsize(14)); label("AA",(1.9411496528285788,-1.0783204767840298),SE*labelscalefactor,fontsize(14)); label("BB",(-2.5046350956841272,-0.9861798602345433),SE*labelscalefactor,fontsize(14)); label("CC",(-2.5737405580962416,3.5747806589650395),SE*labelscalefactor,fontsize(14)); label("11",(-2.665881174645728,1.2712652452278765),SE*labelscalefactor,fontsize(14)); label("11",(-0.3393306067712029,-1.3547423264324894),SE*labelscalefactor,fontsize(14)); /* dots and labels */ dot((-2.,3.),linewidth(4.pt) + dotstyle); dot((-2.,-1.),linewidth(4.pt) + dotstyle); dot((2.,-1.),linewidth(4.pt) + dotstyle); dot((-0.6404058554606791,4.3595941445393205),linewidth(4.pt) + dotstyle); clip((xmin,ymin)--(xmin,ymax)--(xmax,ymax)--(xmax,ymin)--cycle); /* end of picture */ [/asy] <spanclass=latexbold>(A)</span>13<spanclass=latexbold>(B)</span>22<spanclass=latexbold>(C)</span>34<spanclass=latexbold>(D)</span>79<spanclass=latexbold>(E)</span>32<span class='latex-bold'>(A) </span> \dfrac{1}{3} \qquad<span class='latex-bold'>(B) </span> \dfrac{\sqrt{2}}{2} \qquad<span class='latex-bold'>(C) </span> \dfrac{3}{4} \qquad<span class='latex-bold'>(D) </span> \dfrac{7}{9} \qquad<span class='latex-bold'>(E) </span> \dfrac{\sqrt{3}}{2}