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MAA AMC
AMC 12/AHSME
2019 AMC 12/AHSME
2
A is 150% of B
A is 150% of B
Source: 2019 AMC 12A #2
February 8, 2019
percent
AMC
AMC 12
AMC 12 A
2019 AMC 12A
2019 AMC
Problem Statement
Suppose
a
a
a
is
150
%
150\%
150%
of
b
b
b
. What percent of
a
a
a
is
3
b
3b
3
b
?
<
s
p
a
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c
l
a
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=
′
l
a
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x
−
b
o
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′
>
(
A
)
<
/
s
p
a
n
>
50
<
s
p
a
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c
l
a
s
s
=
′
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−
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>
(
B
)
<
/
s
p
a
n
>
66
2
3
<
s
p
a
n
c
l
a
s
s
=
′
l
a
t
e
x
−
b
o
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d
′
>
(
C
)
<
/
s
p
a
n
>
150
<
s
p
a
n
c
l
a
s
s
=
′
l
a
t
e
x
−
b
o
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d
′
>
(
D
)
<
/
s
p
a
n
>
200
<
s
p
a
n
c
l
a
s
s
=
′
l
a
t
e
x
−
b
o
l
d
′
>
(
E
)
<
/
s
p
a
n
>
450
<span class='latex-bold'>(A) </span> 50 \qquad <span class='latex-bold'>(B) </span> 66\frac{2}{3} \qquad <span class='latex-bold'>(C) </span> 150 \qquad <span class='latex-bold'>(D) </span> 200 \qquad <span class='latex-bold'>(E) </span> 450
<
s
p
an
c
l
a
ss
=
′
l
a
t
e
x
−
b
o
l
d
′
>
(
A
)
<
/
s
p
an
>
50
<
s
p
an
c
l
a
ss
=
′
l
a
t
e
x
−
b
o
l
d
′
>
(
B
)
<
/
s
p
an
>
66
3
2
<
s
p
an
c
l
a
ss
=
′
l
a
t
e
x
−
b
o
l
d
′
>
(
C
)
<
/
s
p
an
>
150
<
s
p
an
c
l
a
ss
=
′
l
a
t
e
x
−
b
o
l
d
′
>
(
D
)
<
/
s
p
an
>
200
<
s
p
an
c
l
a
ss
=
′
l
a
t
e
x
−
b
o
l
d
′
>
(
E
)
<
/
s
p
an
>
450
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