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1999 AMC 8
1
1999 AMC 8 #1
1999 AMC 8 #1
Source:
June 17, 2011
Problem Statement
(
6
?
3
)
+
4
−
(
2
−
1
)
=
5.
(6?3)+4-(2-1) = 5.
(
6
?
3
)
+
4
−
(
2
−
1
)
=
5.
To make this statement true, the question mark between the 6 and the 3 should be replaced by
(A)
÷
(B)
×
(C)
+
(D)
−
(E) None of these
\text{(A)}\div\qquad\text{(B)}\ \times\qquad\text{(C)}+\qquad\text{(D)}\ -\qquad\text{(E)}\ \text{None of these}
(A)
÷
(B)
×
(C)
+
(D)
−
(E)
None of these
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