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Part of 1999 AMC 8

Problems(1)

1999 AMC 8 #1

Source:

6/17/2011
(6?3)+4−(2−1)=5. (6?3)+4-(2-1) = 5. To make this statement true, the question mark between the 6 and the 3 should be replaced by
(A)÷(B) ×(C)+(D) −(E) None of these \text{(A)}\div\qquad\text{(B)}\ \times\qquad\text{(C)}+\qquad\text{(D)}\ -\qquad\text{(E)}\ \text{None of these}