MathDB
Projected Particle

Source: AHSME 1963 Problem 29

January 11, 2014
conicsparabolaAMC

Problem Statement

A particle projected vertically upward reaches, at the end of tt seconds, an elevation of ss feet where s=160t16t2s = 160 t - 16t^2. The highest elevation is:
<spanclass=latexbold>(A)</span> 800<spanclass=latexbold>(B)</span> 640<spanclass=latexbold>(C)</span> 400<spanclass=latexbold>(D)</span> 320<spanclass=latexbold>(E)</span> 160<span class='latex-bold'>(A)</span>\ 800 \qquad <span class='latex-bold'>(B)</span>\ 640\qquad <span class='latex-bold'>(C)</span>\ 400 \qquad <span class='latex-bold'>(D)</span>\ 320 \qquad <span class='latex-bold'>(E)</span>\ 160