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Problems
Contests
National and Regional Contests
USA Contests
MAA AMC
AMC 12/AHSME
1963 AMC 12/AHSME
29
29
Part of
1963 AMC 12/AHSME
Problems
(1)
Projected Particle
Source: AHSME 1963 Problem 29
1/11/2014
A particle projected vertically upward reaches, at the end of
t
t
t
seconds, an elevation of
s
s
s
feet where
s
=
160
t
−
16
t
2
s = 160 t - 16t^2
s
=
160
t
−
16
t
2
. The highest elevation is:
<
s
p
a
n
c
l
a
s
s
=
′
l
a
t
e
x
−
b
o
l
d
′
>
(
A
)
<
/
s
p
a
n
>
800
<
s
p
a
n
c
l
a
s
s
=
′
l
a
t
e
x
−
b
o
l
d
′
>
(
B
)
<
/
s
p
a
n
>
640
<
s
p
a
n
c
l
a
s
s
=
′
l
a
t
e
x
−
b
o
l
d
′
>
(
C
)
<
/
s
p
a
n
>
400
<
s
p
a
n
c
l
a
s
s
=
′
l
a
t
e
x
−
b
o
l
d
′
>
(
D
)
<
/
s
p
a
n
>
320
<
s
p
a
n
c
l
a
s
s
=
′
l
a
t
e
x
−
b
o
l
d
′
>
(
E
)
<
/
s
p
a
n
>
160
<span class='latex-bold'>(A)</span>\ 800 \qquad <span class='latex-bold'>(B)</span>\ 640\qquad <span class='latex-bold'>(C)</span>\ 400 \qquad <span class='latex-bold'>(D)</span>\ 320 \qquad <span class='latex-bold'>(E)</span>\ 160
<
s
p
an
c
l
a
ss
=
′
l
a
t
e
x
−
b
o
l
d
′
>
(
A
)
<
/
s
p
an
>
800
<
s
p
an
c
l
a
ss
=
′
l
a
t
e
x
−
b
o
l
d
′
>
(
B
)
<
/
s
p
an
>
640
<
s
p
an
c
l
a
ss
=
′
l
a
t
e
x
−
b
o
l
d
′
>
(
C
)
<
/
s
p
an
>
400
<
s
p
an
c
l
a
ss
=
′
l
a
t
e
x
−
b
o
l
d
′
>
(
D
)
<
/
s
p
an
>
320
<
s
p
an
c
l
a
ss
=
′
l
a
t
e
x
−
b
o
l
d
′
>
(
E
)
<
/
s
p
an
>
160
conics
parabola
AMC