Consider the non-decreasing sequence of positive integers
1,2,2,3,3,3,4,4,4,4,5,5,5,5,5,... in which the nth positive integer appears n times. The remainder when the 1993rd term is divided by 5 is<spanclass=′latex−bold′>(A)</span>0<spanclass=′latex−bold′>(B)</span>1<spanclass=′latex−bold′>(C)</span>2<spanclass=′latex−bold′>(D)</span>3<spanclass=′latex−bold′>(E)</span>4