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Today's Calculation Of Integral
2010 Today's Calculation Of Integral
629
Today's calculation of Integral 629
Today's calculation of Integral 629
Source:
July 9, 2010
calculus
integration
calculus computations
Problem Statement
Evaluate
∫
0
∞
1
e
x
(
1
+
e
4
x
)
d
x
.
\int_0^{\infty} \frac{1}{e^{x}(1+e^{4x})}dx.
∫
0
∞
e
x
(
1
+
e
4
x
)
1
d
x
.
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