MathDB
Problems
Contests
National and Regional Contests
Japan Contests
Today's Calculation Of Integral
2010 Today's Calculation Of Integral
629
629
Part of
2010 Today's Calculation Of Integral
Problems
(1)
Today's calculation of Integral 629
Source:
7/9/2010
Evaluate
∫
0
∞
1
e
x
(
1
+
e
4
x
)
d
x
.
\int_0^{\infty} \frac{1}{e^{x}(1+e^{4x})}dx.
∫
0
∞
e
x
(
1
+
e
4
x
)
1
d
x
.
calculus
integration
calculus computations