In rhombus ABCD, point P lies on segment AD such that BP⊥AD, AP=3, and PD=2. What is the area of ABCD? [asy]
import olympiad;
size(180);
real r = 3, s = 5, t = sqrt(r*r+s*s);
defaultpen(linewidth(0.6) + fontsize(10));
pair A = (0,0), B = (r,s), C = (r+t,s), D = (t,0), P = (r,0);
draw(A--B--C--D--A^^B--P^^rightanglemark(B,P,D));
label("A",A,SW);
label("B", B, NW);
label("C",C,NE);
label("D",D,SE);
label("P",P,S);
[/asy]
<spanclass=′latex−bold′>(A)</span>35<spanclass=′latex−bold′>(B)</span>10<spanclass=′latex−bold′>(C)</span>65<spanclass=′latex−bold′>(D)</span>20<spanclass=′latex−bold′>(E)</span>25