MathDB

Let a geometric progression with

n

terms have first term one, common ratio

r

and sum

s

, where

r

and

s

are not zero. The sum of the geometric progression formed by replacing each term of the original progression by its reciprocal is

<span class='latex-bold'>(A) </span>\frac{1}{s}\qquad<span class='latex-bold'>(B) </span>\frac{1}{r^ns}\qquad<span class='latex-bold'>(C) </span>\frac{s}{r^{n-1}}\qquad<span class='latex-bold'>(D) </span>\frac{r^n}{s}\qquad <span class='latex-bold'>(E) </span>\frac{r^{n-1}}{s}

Problem Statement