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P<= ( r+\sqrt{r^2+4R^2})/2 for bicentric quadr.

Source: VI All-Ukrainian Tournament of Young Mathematicians, Qualifying p14

May 25, 2021
geometrybicentric quadrilateralgeometric inequalityUkrainian TYM

Problem Statement

A quadrilateral whose perimeter is equal to PP is inscribed in a circle of radius RR and is circumscribed around a circle of radius rr. Check whether the inequality Pr+r2+4R22P\le \frac{r+\sqrt{r^2+4R^2}}{2} holds. Try to find the corresponding inequalities for the nn-gon (n5n \ge 5) inscribed in a circle of radius RR and circumscribed around a circle of radius rr.