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Today's Calculation Of Integral
2005 Today's Calculation Of Integral
22
Today's calculation of Integral 22
Today's calculation of Integral 22
Source: 2004 Akita Prefectural University
May 23, 2005
calculus
integration
induction
trigonometry
calculus computations
Problem Statement
Evaluate
∫
0
1
(
1
−
x
2
)
n
d
x
(
n
=
0
,
1
,
2
,
⋯
)
\int_0^1 (1-x^2)^n dx\ (n=0,1,2,\cdots)
∫
0
1
(
1
−
x
2
)
n
d
x
(
n
=
0
,
1
,
2
,
⋯
)
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