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Today's Calculation Of Integral
2005 Today's Calculation Of Integral
22
22
Part of
2005 Today's Calculation Of Integral
Problems
(1)
Today's calculation of Integral 22
Source: 2004 Akita Prefectural University
5/23/2005
Evaluate
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0
1
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1
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2
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n
d
x
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n
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0
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1
,
2
,
⋯
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\int_0^1 (1-x^2)^n dx\ (n=0,1,2,\cdots)
∫
0
1
(
1
−
x
2
)
n
d
x
(
n
=
0
,
1
,
2
,
⋯
)
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integration
induction
trigonometry
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