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Today's calculation of Integral 887

Source: 2013 Shibaura Institute of Technology entrance exam

July 16, 2013
calculusintegrationfunctiontrigonometrylogarithmsderivativecalculus computations

Problem Statement

For the function f(x)=0xdt1+t2f(x)=\int_0^x \frac{dt}{1+t^2}, answer the questions as follows.
Note : Please solve the problems without using directly the formula 11+x2 dx=tan1x+C\int \frac{1}{1+x^2}\ dx=\tan^{-1}x +C for Japanese High School students those who don't study arc sin x, arc cos x, arc tanx.
(1) Find f(3)f(\sqrt{3})
(2) Find 03xf(x) dx\int_0^{\sqrt{3}} xf(x)\ dx
(3) Prove that for x>0x>0. f(x)+f(1x)f(x)+f\left(\frac{1}{x}\right) is constant, then find the value.