MathDB
1987 AMC 12 #26 - Probability

Source:

January 1, 2012
probabilityAMC

Problem Statement

The amount 2.52.5 is split into two nonnegative real numbers uniformly at random, for instance, into 2.1432.143 and .357.357, or into 3\sqrt{3} and 2.53.2.5-\sqrt{3}. Then each number is rounded to its nearest integer, for instance, 22 and 00 in the first case above, 22 and 11 in the second. What is the probability that the two integers sum to 33?
<spanclass=latexbold>(A)</span> 14<spanclass=latexbold>(B)</span> 25<spanclass=latexbold>(C)</span> 12<spanclass=latexbold>(D)</span> 35<spanclass=latexbold>(E)</span> 34 <span class='latex-bold'>(A)</span>\ \frac{1}{4} \qquad<span class='latex-bold'>(B)</span>\ \frac{2}{5} \qquad<span class='latex-bold'>(C)</span>\ \frac{1}{2} \qquad<span class='latex-bold'>(D)</span>\ \frac{3}{5} \qquad<span class='latex-bold'>(E)</span>\ \frac{3}{4}