[asy]
size(2.5inch);
pair A, B, C, E, F, G;
A = (0,3);
B = (-1,0);
C = (3,0);
E = (0,0);
F = (1,2);
G = intersectionpoint(B--F,A--E);
draw(A--B--C--cycle);
draw(A--E);
draw(B--F);
label("A",A,N);
label("B",B,W);
label("C",C,dir(0));
label("E",E,S);
label("F",F,NE);
label("G",G,SE);
//Credit to chezbgone2 for the diagram[/asy]In triangle ABC, point F divides side AC in the ratio 1:2. Let E be the point of intersection of side BC and AG where G is the midpoints of BF. The point E divides side BC in the ratio<spanclass=′latex−bold′>(A)</span>1:4<spanclass=′latex−bold′>(B)</span>1:3<spanclass=′latex−bold′>(C)</span>2:5<spanclass=′latex−bold′>(D)</span>4:11<spanclass=′latex−bold′>(E)</span>3:8