Prove that $2\log_3 n \leq f(n) < 5\log_3 n$ for every $n>1$.
Source: Moldova TST 2001
August 6, 2023
Problem Statement
For every nonnegative integer n let f(n) be the smallest number of digits 1 which can represent the number n using the symbols "+","−","×","(",")". For example, 80=(1+1+1+1+1)×(1+1+1+1)×(1+1+1+1) and f(80)≤13. Prove that 2log3n≤f(n)<5log3n for every n>1.