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Arithmetic to Geometric Progression

Source: AHSME 1963 Problem 16

January 9, 2014
ratioAMC

Problem Statement

Three numbers a,b,ca,b,c, none zero, form an arithmetic progression. Increasing aa by 11 or increasing cc by 22 results in a geometric progression. Then bb equals:
<spanclass=′latex−bold′>(A)</span> 16<spanclass=′latex−bold′>(B)</span> 14<spanclass=′latex−bold′>(C)</span> 12<spanclass=′latex−bold′>(D)</span> 10<spanclass=′latex−bold′>(E)</span> 8<span class='latex-bold'>(A)</span>\ 16 \qquad <span class='latex-bold'>(B)</span>\ 14 \qquad <span class='latex-bold'>(C)</span>\ 12 \qquad <span class='latex-bold'>(D)</span>\ 10 \qquad <span class='latex-bold'>(E)</span>\ 8
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