MathDB
1996 AJHSME Problem 15

Source:

July 10, 2011
AMC

Problem Statement

The remainder when the product 1492⋅1776⋅1812⋅19961492\cdot 1776\cdot 1812\cdot 1996 is divided by 55 is
(A) 0(B) 1(C) 2(D) 3(E) 4\text{(A)}\ 0 \qquad \text{(B)}\ 1 \qquad \text{(C)}\ 2 \qquad \text{(D)}\ 3 \qquad \text{(E)}\ 4
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