MathDB
Logic

Source: 1968 AHSME Problem #10

August 31, 2011
AMC

Problem Statement

Assume that, for a certain school, it is true that I: Some students are not honest II: All fraternity members are honest A necessary conclusion is:
<spanclass=latexbold>(A)</span> Some students are fraternity members<spanclass=latexbold>(B)</span> Some fraternity members are not students<spanclass=latexbold>(C)</span> Some students are not fraternity members<spanclass=latexbold>(D)</span> No fraternity member is a student<spanclass=latexbold>(E)</span> No student is a fraternity member<span class='latex-bold'>(A)</span>\ \text{Some students are fraternity members} \qquad\\ <span class='latex-bold'>(B)</span>\ \text{Some fraternity members are not students} \qquad\\ <span class='latex-bold'>(C)</span>\ \text{Some students are not fraternity members} \qquad\\ <span class='latex-bold'>(D)</span>\ \text{No fraternity member is a student} \qquad\\ <span class='latex-bold'>(E)</span>\ \text{No student is a fraternity member}