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2023 CUBRMC
9
2023 CUBRMC Team #9 n|1+\sum^{n-1}_{k=1}k^{2k}
2023 CUBRMC Team #9 n|1+\sum^{n-1}_{k=1}k^{2k}
Source:
March 8, 2024
number theory
cubrmc
Problem Statement
Find the sum of all integers
n
n
n
such that
1
<
n
<
30
1 < n < 30
1
<
n
<
30
and
n
n
n
divides
1
+
∑
k
=
1
n
−
1
k
2
k
.
1+\sum^{n-1}_{k=1}k^{2k}.
1
+
k
=
1
∑
n
−
1
k
2
k
.
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