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AHSME 1950- part 3

Source:

July 20, 2008

Problem Statement

A privateer discovers a merchantman 1010 miles to leeward at 11:45 a.m. and with a good breeze bears down upon her at 1111 mph, while the merchantman can only make 88 mph in her attempt to escape. After a two hour chase, the top sail of the privateer is carried away; she can now make only 1717 miles while the merchantman makes 1515. The privateer will overtake the merchantman at:
<spanclass=′latex−bold′>(A)</span> 3:45 p.m.<spanclass=′latex−bold′>(B)</span> 3:30 p.m.<spanclass=′latex−bold′>(C)</span> 5:00 p.m.<spanclass=′latex−bold′>(D)</span> 2:45 p.m.<spanclass=′latex−bold′>(E)</span> 5:30 p.m.<span class='latex-bold'>(A)</span>\ 3\text{:}45\text{ p.m.} \qquad <span class='latex-bold'>(B)</span>\ 3\text{:}30\text{ p.m.} \qquad <span class='latex-bold'>(C)</span>\ 5\text{:}00\text{ p.m.} \qquad <span class='latex-bold'>(D)</span>\ 2\text{:}45\text{ p.m.} \qquad <span class='latex-bold'>(E)</span>\ 5\text{:}30\text{ p.m.}
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