MathDB
Problems
Contests
National and Regional Contests
Japan Contests
Today's Calculation Of Integral
2010 Today's Calculation Of Integral
596
Today's calculation of Integral 596
Today's calculation of Integral 596
Source:
April 23, 2010
calculus
integration
trigonometry
calculus computations
Problem Statement
Find the minimum value of
∫
0
π
2
∣
a
sin
2
x
−
cos
2
x
∣
d
x
(
a
>
0
)
.
\int_0^{\frac{\pi}{2}} |a\sin 2x-\cos ^ 2 x|dx\ (a>0).
∫
0
2
π
∣
a
sin
2
x
−
cos
2
x
∣
d
x
(
a
>
0
)
.
2009 Shimane University entrance exam/Medicine
Back to Problems
View on AoPS