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Today's Calculation Of Integral
2010 Today's Calculation Of Integral
596
596
Part of
2010 Today's Calculation Of Integral
Problems
(1)
Today's calculation of Integral 596
Source:
4/23/2010
Find the minimum value of
∫
0
π
2
∣
a
sin
2
x
−
cos
2
x
∣
d
x
(
a
>
0
)
.
\int_0^{\frac{\pi}{2}} |a\sin 2x-\cos ^ 2 x|dx\ (a>0).
∫
0
2
π
∣
a
sin
2
x
−
cos
2
x
∣
d
x
(
a
>
0
)
.
2009 Shimane University entrance exam/Medicine
calculus
integration
trigonometry
calculus computations