MathDB
1996 AJHSME Problem 16

Source:

July 10, 2011
AMC

Problem Statement

1−2−3+4+5−6−7+8+9−10−11+⋯+1992+1993−1994−1995+1996=1-2-3+4+5-6-7+8+9-10-11+\cdots + 1992+1993-1994-1995+1996=
(A) −998(B) −1(C) 0(D) 1(E) 998\text{(A)}\ -998 \qquad \text{(B)}\ -1 \qquad \text{(C)}\ 0 \qquad \text{(D)}\ 1 \qquad \text{(E)}\ 998
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