MathDB
Circumradius

Source: 1959 AHSME Problem 43

August 14, 2013
geometrycircumcirclearea of a triangleHeron's formulaAMCcircumradiuscircle

Problem Statement

The sides of a triangle are 25,39,25,39, and 4040. The diameter of the circumscribed circle is: <spanclass=′latex−bold′>(A)</span> 1333<spanclass=′latex−bold′>(B)</span> 1253<spanclass=′latex−bold′>(C)</span> 42<spanclass=′latex−bold′>(D)</span> 41<spanclass=′latex−bold′>(E)</span> 40 <span class='latex-bold'>(A)</span>\ \frac{133}{3}\qquad<span class='latex-bold'>(B)</span>\ \frac{125}{3}\qquad<span class='latex-bold'>(C)</span>\ 42\qquad<span class='latex-bold'>(D)</span>\ 41\qquad<span class='latex-bold'>(E)</span>\ 40
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