MathDB
Law of cosines?

Source: 1959 AHSME Problem 36

August 14, 2013
trigonometryAMCTriangle GeometrygeometryAMC 12

Problem Statement

The base of a triangle is 8080, and one side of the base angle is 6060^\circ. The sum of the lengths of the other two sides is 9090. The shortest side is: <spanclass=latexbold>(A)</span> 45<spanclass=latexbold>(B)</span> 40<spanclass=latexbold>(C)</span> 36<spanclass=latexbold>(D)</span> 17<spanclass=latexbold>(E)</span> 12 <span class='latex-bold'>(A)</span>\ 45 \qquad<span class='latex-bold'>(B)</span>\ 40\qquad<span class='latex-bold'>(C)</span>\ 36\qquad<span class='latex-bold'>(D)</span>\ 17\qquad<span class='latex-bold'>(E)</span>\ 12