MathDB
Father and son's ages

Source: 1971 AHSME Problem 25

April 22, 2014
absolute valueAMC

Problem Statement

A teen age boy wrote his own age after his father's. From this new four place number, he subtracted the absolute value of the difference of their ages to get 4,2894,289. The sum of their ages was
<spanclass=latexbold>(A)</span>48<spanclass=latexbold>(B)</span>52<spanclass=latexbold>(C)</span>56<spanclass=latexbold>(D)</span>59<spanclass=latexbold>(E)</span>64<span class='latex-bold'>(A) </span>48\qquad<span class='latex-bold'>(B) </span>52\qquad<span class='latex-bold'>(C) </span>56\qquad<span class='latex-bold'>(D) </span>59\qquad <span class='latex-bold'>(E) </span>64