MathDB
The classical arithmetic mean problem

Source: 1959 AMC 12 Problem 13

August 13, 2013
AMCarithmetic meanalgebraAMC 12

Problem Statement

The arithmetic mean (average) of a set of 5050 numbers is 3838. If two numbers, namely, 4545 and 5555, are discarded, the mean of the remaining set of numbers is: <spanclass=latexbold>(A)</span> 36.5<spanclass=latexbold>(B)</span> 37<spanclass=latexbold>(C)</span> 37.2<spanclass=latexbold>(D)</span> 37.5<spanclass=latexbold>(E)</span> 37.52 <span class='latex-bold'>(A)</span>\ 36.5 \qquad<span class='latex-bold'>(B)</span>\ 37\qquad<span class='latex-bold'>(C)</span>\ 37.2\qquad<span class='latex-bold'>(D)</span>\ 37.5\qquad<span class='latex-bold'>(E)</span>\ 37.52