If f(n)=31n(n1)(n+2), then f(r)−f(r−1) equals:<spanclass=′latex−bold′>(A)</span>r(r+1)<spanclass=′latex−bold′>(B)</span>(r+1)(r+2)<spanclass=′latex−bold′>(C)</span>31r(r+1)<spanclass=′latex−bold′>(D)</span>31(r+1)(r+2)<spanclass=′latex−bold′>(E)</span>31r(r+1)(r+2)