MathDB
Quadratics

Source: AHSME 1986 problem 13

October 1, 2011
quadraticsconicsparabolaAMC

Problem Statement

A parabola y=ax2+bx+cy = ax^{2} + bx + c has vertex (4,2)(4,2). If (2,0)(2,0) is on the parabola, then abcabc equals
<spanclass=′latex−bold′>(A)</span> −12<spanclass=′latex−bold′>(B)</span> −6<spanclass=′latex−bold′>(C)</span> 0<spanclass=′latex−bold′>(D)</span> 6<spanclass=′latex−bold′>(E)</span> 12 <span class='latex-bold'>(A)</span>\ -12\qquad<span class='latex-bold'>(B)</span>\ -6\qquad<span class='latex-bold'>(C)</span>\ 0\qquad<span class='latex-bold'>(D)</span>\ 6\qquad<span class='latex-bold'>(E)</span>\ 12
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