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Contests
National and Regional Contests
USA Contests
MAA AMC
AMC 12/AHSME
1971 AMC 12/AHSME
1
Find the number of digits
Find the number of digits
Source: 1971 AHSME Problem 1
April 17, 2014
FTW
AMC
Problem Statement
The number of digits in the number
N
=
2
12
×
5
8
N=2^{12}\times 5^8
N
=
2
12
×
5
8
is
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A
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9
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B
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10
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C
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11
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D
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12
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E
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20
<span class='latex-bold'>(A) </span>9\qquad<span class='latex-bold'>(B) </span>10\qquad<span class='latex-bold'>(C) </span>11\qquad<span class='latex-bold'>(D) </span>12\qquad <span class='latex-bold'>(E) </span>20
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9
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10
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C
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11
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12
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E
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20
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