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Today's Calculation of Integral 57

Source: 1996 Gakusyuin University

June 29, 2005
calculusintegrationtrigonometrycalculus computations

Problem Statement

Find the value of nNn\in{\mathbb{N}} satisfying the following inequality. 0πx2sinnx dx<99π2100n\left|\int_0^{\pi} x^2\sin nx\ dx\right|<\frac{99\pi ^ 2}{100n}