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Today's Calculation Of Integral
2005 Today's Calculation Of Integral
57
57
Part of
2005 Today's Calculation Of Integral
Problems
(1)
Today's Calculation of Integral 57
Source: 1996 Gakusyuin University
6/29/2005
Find the value of
n
∈
N
n\in{\mathbb{N}}
n
∈
N
satisfying the following inequality.
∣
∫
0
π
x
2
sin
n
x
d
x
∣
<
99
π
2
100
n
\left|\int_0^{\pi} x^2\sin nx\ dx\right|<\frac{99\pi ^ 2}{100n}
∫
0
π
x
2
sin
n
x
d
x
<
100
n
99
π
2
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