MathDB
Today's calculation of Integral 181

Source: Keio University entrance exam/medical 2007

February 23, 2007
calculusintegrationtrigonometryfunctionderivativelogarithmsanalytic geometry

Problem Statement

For real number a,a, find the minimum value of ∫0π2∣sin⁡2x1+sin⁡2x−acos⁡x∣dx.\int_{0}^{\frac{\pi}{2}}\left|\frac{\sin 2x}{1+\sin^{2}x}-a\cos x\right| dx.
Back to ProblemsView on AoPS