181

Part of 2007 Today's Calculation Of Integral

Problems(1)

Today's calculation of Integral 181

Source: Keio University entrance exam/medical 2007

For real number

a,

find the minimum value of

\int_{0}^{\frac{\pi}{2}}\left|\frac{\sin 2x}{1+\sin^{2}x}-a\cos x\right| dx.

calculusintegrationtrigonometryfunctionderivativelogarithmsanalytic geometry