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Belarus Team Selection Test
1998 Belarus Team Selection Test
1
x^3= f( [ x ] ) + g(x)
x^3= f( [ x ] ) + g(x)
Source: 1998 Belarus TST 1.1
December 25, 2020
functional
functional equation
algebra
periodic
Problem Statement
Do there exist functions
f
:
R
→
R
f : R \to R
f
:
R
→
R
and
g
:
R
→
R
g : R \to R
g
:
R
→
R
,
g
g
g
being periodic, such that
x
3
=
f
(
⌊
x
⌋
)
+
g
(
x
)
x^3= f(\lfloor x \rfloor ) + g(x)
x
3
=
f
(⌊
x
⌋)
+
g
(
x
)
for all real
x
x
x
?
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