MathDB
S 8

Source:

May 25, 2007
arithmetic sequenceMiscellaneous Problems

Problem Statement

The set S={1n    nN}S=\{ \frac{1}{n} \; \vert \; n \in \mathbb{N} \} contains arithmetic progressions of various lengths. For instance, 120\frac{1}{20}, 18\frac{1}{8}, 15\frac{1}{5} is such a progression of length 33 and common difference 340\frac{3}{40}. Moreover, this is a maximal progression in SS since it cannot be extended to the left or the right within SS (1140\frac{11}{40} and 140\frac{-1}{40} not being members of SS). Prove that for all nNn \in \mathbb{N}, there exists a maximal arithmetic progression of length nn in SS.