The set S={n1∣n∈N} contains arithmetic progressions of various lengths. For instance, 201, 81, 51 is such a progression of length 3 and common difference 403. Moreover, this is a maximal progression in S since it cannot be extended to the left or the right within S (4011 and 40−1 not being members of S). Prove that for all n∈N, there exists a maximal arithmetic progression of length n in S. arithmetic sequenceMiscellaneous Problems