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1/(1+1/(2+1/3))=

Source: 1993 AMC 8 Problem 16

June 28, 2011
AMC

Problem Statement

11+12+13=\dfrac{1}{1+\dfrac{1}{2+\dfrac{1}{3}}} =
(A) 16(B) 310(C) 710(D) 56(E) 103\text{(A)}\ \dfrac{1}{6} \qquad \text{(B)}\ \dfrac{3}{10} \qquad \text{(C)}\ \dfrac{7}{10} \qquad \text{(D)}\ \dfrac{5}{6} \qquad \text{(E)}\ \dfrac{10}{3}