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AMC 8
1993 AMC 8
16
16
Part of
1993 AMC 8
Problems
(1)
1/(1+1/(2+1/3))=
Source: 1993 AMC 8 Problem 16
6/28/2011
1
1
+
1
2
+
1
3
=
\dfrac{1}{1+\dfrac{1}{2+\dfrac{1}{3}}} =
1
+
2
+
3
1
1
1
=
(A)
1
6
(B)
3
10
(C)
7
10
(D)
5
6
(E)
10
3
\text{(A)}\ \dfrac{1}{6} \qquad \text{(B)}\ \dfrac{3}{10} \qquad \text{(C)}\ \dfrac{7}{10} \qquad \text{(D)}\ \dfrac{5}{6} \qquad \text{(E)}\ \dfrac{10}{3}
(A)
6
1
(B)
10
3
(C)
10
7
(D)
6
5
(E)
3
10
AMC