MathDB

2009 Calculus #10: Definite Integral Closed Form

Source:

June 23, 2012

calculusintegrationtrigonometryfunctionderivativegeometric series

Problem Statement

Let

a

and

b

be real numbers satisfying

a>b>0

. Evaluate

\int_0^{2\pi}\dfrac{1}{a+b\cos(\theta)}d\theta.

Express your answer in terms of

a

and

b