MathDB
Triangle geometry again

Source: 1959 AHSME Problem 26

August 14, 2013
geometryAMCtriangle areaAMC 12

Problem Statement

The base of an isosceles triangle is 2\sqrt 2. The medians to the leg intersect each other at right angles. The area of the triangle is: <spanclass=latexbold>(A)</span> 1.5<spanclass=latexbold>(B)</span> 2<spanclass=latexbold>(C)</span> 2.5<spanclass=latexbold>(D)</span> 3.5<spanclass=latexbold>(E)</span> 4 <span class='latex-bold'>(A)</span>\ 1.5 \qquad<span class='latex-bold'>(B)</span>\ 2\qquad<span class='latex-bold'>(C)</span>\ 2.5\qquad<span class='latex-bold'>(D)</span>\ 3.5\qquad<span class='latex-bold'>(E)</span>\ 4