MathDB
<ACX=<BCY if AX x BX / CX^2 = AY x BY / CY^2

Source: 2011 Belarus TST 2.2

June 14, 2020
equal anglesgeometry

Problem Statement

Two different points X,YX,Y are marked on the side ABAB of a triangle ABCABC so that AX⋅BXCX2=AY⋅BYCY2\frac{AX \cdot BX}{CX^2}=\frac{AY \cdot BY}{CY^2} . Prove that ∠ACX=∠BCY\angle ACX=\angle BCY.
I.Zhuk
Back to ProblemsView on AoPS