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Ratio of second average to first

Source: 1971 AHSME Problem 16

April 20, 2014
ratioAMC

Problem Statement

After finding the average of 3535 scores, a student carelessly included the average with the 3535 scores and found the average of these 3636 numbers. The ratio of the second average to the true average was
<spanclass=latexbold>(A)</span>1:1<spanclass=latexbold>(B)</span>35:36<spanclass=latexbold>(C)</span>36:35<spanclass=latexbold>(D)</span>2:1<spanclass=latexbold>(E)</span>None of these<span class='latex-bold'>(A) </span>1:1\qquad<span class='latex-bold'>(B) </span>35:36\qquad<span class='latex-bold'>(C) </span>36:35\qquad<span class='latex-bold'>(D) </span>2:1\qquad <span class='latex-bold'>(E) </span>\text{None of these}