Today's calculation of Integral 276
Source:
January 23, 2008
calculusintegrationtrigonometrycalculus computations
Problem Statement
Prove that \int_{\frac{1}{n}}^{\pi \minus{}\frac{1}{n}} \frac{1}{\sqrt[3]{\sin x}}\ dx\leq \frac{3}{2}\pi \ (n\equal{}1,\ 2,\ 3,\ \cdots).