276

Part of 2008 Today's Calculation Of Integral

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Today's calculation of Integral 276

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Prove that \int_{\frac{1}{n}}^{\pi \minus{}\frac{1}{n}} \frac{1}{\sqrt[3]{\sin x}}\ dx\leq \frac{3}{2}\pi \ (n\equal{}1,\ 2,\ 3,\ \cdots).

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