MathDB
Does null Minkowski sum imply a function is linear?

Source: Miklós Schweitzer 2014, problem 7

November 16, 2014
functionreal analysistopologyreal analysis unsolved

Problem Statement

Let f:RRf : \mathbb{R} \to \mathbb{R} be a continuous function and let g:RRg : \mathbb{R} \to \mathbb{R} be arbitrary. Suppose that the Minkowski sum of the graph of ff and the graph of gg (i.e., the set {(x+y;f(x)+g(y))x,yR}\{( x+y; f(x)+g(y) ) \mid x, y \in \mathbb{R}\}) has Lebesgue measure zero. Does it follow then that the function ff is of the form f(x)=ax+bf(x) = ax + b with suitable constants a,bRa, b \in \mathbb{R} ?