Let f:R→R be a continuous function and let g:R→R be arbitrary. Suppose that the Minkowski sum of the graph of f and the graph of g (i.e., the set {(x+y;f(x)+g(y))∣x,y∈R}) has Lebesgue measure zero. Does it follow then that the function f is of the form f(x)=ax+b with suitable constants a,b∈R ? functionreal analysistopologyreal analysis unsolved